php-src/tests/lang/bug24658.phpt
Gabriel Caruso ce1d69a1f6 Use int instead of integer in type errors
PHP requires integer typehints to be written "int" and does not
allow "integer" as an alias. This changes type error messages to
match the actual type name and avoids confusing messages like
"must be of the type integer, integer given".
2018-02-04 19:08:23 +01:00

62 lines
1.1 KiB
PHP

--TEST--
Bug #24658 (combo of typehint / reference causes crash)
--FILE--
<?php
class foo {}
function no_typehint($a) {
var_dump($a);
}
function typehint(foo $a) {
var_dump($a);
}
function no_typehint_ref(&$a) {
var_dump($a);
}
function typehint_ref(foo &$a) {
var_dump($a);
}
$v = new foo();
$a = array(new foo(), 1, 2);
no_typehint($v);
typehint($v);
no_typehint_ref($v);
typehint_ref($v);
echo "===no_typehint===\n";
array_walk($a, 'no_typehint');
echo "===no_typehint_ref===\n";
array_walk($a, 'no_typehint_ref');
echo "===typehint===\n";
array_walk($a, 'typehint');
echo "===typehint_ref===\n";
array_walk($a, 'typehint_ref');
?>
--EXPECTF--
object(foo)#%d (0) {
}
object(foo)#%d (0) {
}
object(foo)#%d (0) {
}
object(foo)#%d (0) {
}
===no_typehint===
object(foo)#%d (0) {
}
int(1)
int(2)
===no_typehint_ref===
object(foo)#%d (0) {
}
int(1)
int(2)
===typehint===
object(foo)#%d (0) {
}
Fatal error: Uncaught TypeError: Argument 1 passed to typehint() must be an instance of foo, int given in %s:%d
Stack trace:
#0 [internal function]: typehint(1, 1)
#1 %s(%d): array_walk(Array, 'typehint')
#2 {main}
thrown in %s on line %d